m^2-9m/8=0

Solution for m^2-9m/8=0 equation:

m^2-9m/8=0

We multiply all the terms by the denominator


m^2*8-9m=0

Wy multiply elements

8m^2-9m=0

a = 8; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·8·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*8}=\frac{0}{16}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*8}=\frac{18}{16}
=1+1/8
$